16+3(4y-5)=7

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Solution for 16+3(4y-5)=7 equation: 



16+3(4y-5)=7

We move all terms to the left:

16+3(4y-5)-(7)=0

We add all the numbers together, and all the variables

3(4y-5)+9=0

We multiply parentheses

12y-15+9=0

We add all the numbers together, and all the variables

12y-6=0

We move all terms containing y to the left, all other terms to the right

12y=6

y=6/12

y=1/2

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