16+3x+(4x-3)=(2x)4

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Solution for 16+3x+(4x-3)=(2x)4 equation:


Simplifying
16 + 3x + (4x + -3) = (2x) * 4

Reorder the terms:
16 + 3x + (-3 + 4x) = (2x) * 4

Remove parenthesis around (-3 + 4x)
16 + 3x + -3 + 4x = (2x) * 4

Reorder the terms:
16 + -3 + 3x + 4x = (2x) * 4

Combine like terms: 16 + -3 = 13
13 + 3x + 4x = (2x) * 4

Combine like terms: 3x + 4x = 7x
13 + 7x = (2x) * 4

Remove parenthesis around (2x)
13 + 7x = 2x * 4

Reorder the terms for easier multiplication:
13 + 7x = 2 * 4x

Multiply 2 * 4
13 + 7x = 8x

Solving
13 + 7x = 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
13 + 7x + -8x = 8x + -8x

Combine like terms: 7x + -8x = -1x
13 + -1x = 8x + -8x

Combine like terms: 8x + -8x = 0
13 + -1x = 0

Add '-13' to each side of the equation.
13 + -13 + -1x = 0 + -13

Combine like terms: 13 + -13 = 0
0 + -1x = 0 + -13
-1x = 0 + -13

Combine like terms: 0 + -13 = -13
-1x = -13

Divide each side by '-1'.
x = 13

Simplifying
x = 13

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