16+3x=1+6(4-x)

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Solution for 16+3x=1+6(4-x) equation: 



16+3x=1+6(4-x)

We move all terms to the left:

16+3x-(1+6(4-x))=0

We add all the numbers together, and all the variables

3x-(1+6(-1x+4))+16=0



We calculate terms in parentheses: -(1+6(-1x+4)), so:

1+6(-1x+4)

determiningTheFunctionDomain
6(-1x+4)+1

We multiply parentheses

-6x+24+1

We add all the numbers together, and all the variables

-6x+25

Back to the equation:

-(-6x+25)



We get rid of parentheses

3x+6x-25+16=0

We add all the numbers together, and all the variables

9x-9=0

We move all terms containing x to the left, all other terms to the right

9x=9

x=9/9

x=1

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