16+4(3x-6)=40

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Solution for 16+4(3x-6)=40 equation: 



16+4(3x-6)=40

We move all terms to the left:

16+4(3x-6)-(40)=0

We add all the numbers together, and all the variables

4(3x-6)-24=0

We multiply parentheses

12x-24-24=0

We add all the numbers together, and all the variables

12x-48=0

We move all terms containing x to the left, all other terms to the right

12x=48

x=48/12

x=4

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