16-(-2x-4)-(5x-3+2)=-4x-(-8x+2)

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Solution for 16-(-2x-4)-(5x-3+2)=-4x-(-8x+2) equation: 



16-(-2x-4)-(5x-3+2)=-4x-(-8x+2)

We move all terms to the left:

16-(-2x-4)-(5x-3+2)-(-4x-(-8x+2))=0

We add all the numbers together, and all the variables

-(-2x-4)-(5x-1)-(-4x-(-8x+2))+16=0

We get rid of parentheses

2x-5x-(-4x-(-8x+2))+4+1+16=0



We calculate terms in parentheses: -(-4x-(-8x+2)), so:

-4x-(-8x+2)

We get rid of parentheses

-4x+8x-2

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We add all the numbers together, and all the variables

-3x-(4x-2)+21=0

We get rid of parentheses

-3x-4x+2+21=0

We add all the numbers together, and all the variables

-7x+23=0

We move all terms containing x to the left, all other terms to the right

-7x=-23

x=-23/-7

x=3+2/7

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