16-(1/2)x=(3/4)x+1

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Solution for 16-(1/2)x=(3/4)x+1 equation:



16-(1/2)x=(3/4)x+1
We move all terms to the left:
16-(1/2)x-((3/4)x+1)=0
Domain of the equation: 2)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 4)x+1)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
-(+1/2)x-((+3/4)x+1)+16=0
We multiply parentheses
-x^2-((+3/4)x+1)+16=0
We multiply all the terms by the denominator
-x^2*4)x+1)-((+16*4)x+1)+3=0
We add all the numbers together, and all the variables
-x^2*4)x+1)-(64x+1)+3=0
Wy multiply elements
-4x^3=0
We do not support expression: x^3

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