16-(11/5y)-y=0

Solution for 16-(11/5y)-y=0 equation:

16-(11/5y)-y=0


Domain of the equation: 5y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

-(+11/5y)-y+16=0

We add all the numbers together, and all the variables

-1y-(+11/5y)+16=0

We get rid of parentheses

-1y-11/5y+16=0

We multiply all the terms by the denominator


-1y*5y+16*5y-11=0

Wy multiply elements

-5y^2+80y-11=0

a = -5; b = 80; c = -11;
Δ = b2-4ac
Δ = 802-4·(-5)·(-11)
Δ = 6180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6180}=\sqrt{4*1545}=\sqrt{4}*\sqrt{1545}=2\sqrt{1545}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-2\sqrt{1545}}{2*-5}=\frac{-80-2\sqrt{1545}}{-10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+2\sqrt{1545}}{2*-5}=\frac{-80+2\sqrt{1545}}{-10}
$