16-(2-3i)-i=1

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Solution for 16-(2-3i)-i=1 equation: 



16-(2-3i)-i=1

We move all terms to the left:

16-(2-3i)-i-(1)=0

We add all the numbers together, and all the variables

-(-3i+2)-i+16-1=0

We add all the numbers together, and all the variables

-1i-(-3i+2)+15=0

We get rid of parentheses

-1i+3i-2+15=0

We add all the numbers together, and all the variables

2i+13=0

We move all terms containing i to the left, all other terms to the right

2i=-13

i=-13/2

i=-6+1/2

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