16-(2-3i)-i=14+2i

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Solution for 16-(2-3i)-i=14+2i equation: 



16-(2-3i)-i=14+2i

We move all terms to the left:

16-(2-3i)-i-(14+2i)=0

We add all the numbers together, and all the variables

-(-3i+2)-i-(2i+14)+16=0

We add all the numbers together, and all the variables

-1i-(-3i+2)-(2i+14)+16=0

We get rid of parentheses

-1i+3i-2i-2-14+16=0

We add all the numbers together, and all the variables

=0

i=0/1

i=0

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