16-(2x+12)=4+(8x+20)

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Solution for 16-(2x+12)=4+(8x+20) equation:



16-(2x+12)=4+(8x+20)
We move all terms to the left:
16-(2x+12)-(4+(8x+20))=0
We get rid of parentheses
-2x-(4+(8x+20))-12+16=0
We calculate terms in parentheses: -(4+(8x+20)), so:
4+(8x+20)
determiningTheFunctionDomain (8x+20)+4
We get rid of parentheses
8x+20+4
We add all the numbers together, and all the variables
8x+24
Back to the equation:
-(8x+24)
We add all the numbers together, and all the variables
-2x-(8x+24)+4=0
We get rid of parentheses
-2x-8x-24+4=0
We add all the numbers together, and all the variables
-10x-20=0
We move all terms containing x to the left, all other terms to the right
-10x=20
x=20/-10
x=-2

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