16-(2x-4)-(5x-3x+2)=-4x-(-8x+2)

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Solution for 16-(2x-4)-(5x-3x+2)=-4x-(-8x+2) equation: 



16-(2x-4)-(5x-3x+2)=-4x-(-8x+2)

We move all terms to the left:

16-(2x-4)-(5x-3x+2)-(-4x-(-8x+2))=0

We add all the numbers together, and all the variables

-(2x-4)-(2x+2)-(-4x-(-8x+2))+16=0

We get rid of parentheses

-2x-2x-(-4x-(-8x+2))+4-2+16=0



We calculate terms in parentheses: -(-4x-(-8x+2)), so:

-4x-(-8x+2)

We get rid of parentheses

-4x+8x-2

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We add all the numbers together, and all the variables

-4x-(4x-2)+18=0

We get rid of parentheses

-4x-4x+2+18=0

We add all the numbers together, and all the variables

-8x+20=0

We move all terms containing x to the left, all other terms to the right

-8x=-20

x=-20/-8

x=2+1/2

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