16-(3+9x-4(x+4))=-3(5x-4)-(8(x-1)-10x+7)

Solution for 16-(3+9x-4(x+4))=-3(5x-4)-(8(x-1)-10x+7) equation:

16-(3+9x-4(x+4))=-3(5x-4)-(8(x-1)-10x+7)

We move all terms to the left:

16-(3+9x-4(x+4))-(-3(5x-4)-(8(x-1)-10x+7))=0


We calculate terms in parentheses: -(3+9x-4(x+4)), so:

3+9x-4(x+4)

determiningTheFunctionDomain
9x-4(x+4)+3

We multiply parentheses

9x-4x-16+3

We add all the numbers together, and all the variables

5x-13

Back to the equation:

-(5x-13)



We calculate terms in parentheses: -(-3(5x-4)-(8(x-1)-10x+7)), so:

-3(5x-4)-(8(x-1)-10x+7)

We multiply parentheses

-15x-(8(x-1)-10x+7)+12


We calculate terms in parentheses: -(8(x-1)-10x+7), so:

8(x-1)-10x+7

We add all the numbers together, and all the variables

-10x+8(x-1)+7

We multiply parentheses

-10x+8x-8+7

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)


We get rid of parentheses

-15x+2x+1+12

We add all the numbers together, and all the variables

-13x+13

Back to the equation:

-(-13x+13)


We get rid of parentheses

-5x+13x+13-13+16=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2