16-(3c+4)=3c

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Solution for 16-(3c+4)=3c equation: 



16-(3c+4)=3c

We move all terms to the left:

16-(3c+4)-(3c)=0

We add all the numbers together, and all the variables

-3c-(3c+4)+16=0

We get rid of parentheses

-3c-3c-4+16=0

We add all the numbers together, and all the variables

-6c+12=0

We move all terms containing c to the left, all other terms to the right

-6c=-12

c=-12/-6

c=+2

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