16-(7m+3)=8(1-m)=8

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Solution for 16-(7m+3)=8(1-m)=8 equation: 



16-(7m+3)=8(1-m)=8

We move all terms to the left:

16-(7m+3)-(8(1-m))=0

We add all the numbers together, and all the variables

-(7m+3)-(8(-1m+1))+16=0

We get rid of parentheses

-7m-(8(-1m+1))-3+16=0



We calculate terms in parentheses: -(8(-1m+1)), so:

8(-1m+1)

We multiply parentheses

-8m+8

Back to the equation:

-(-8m+8)



We add all the numbers together, and all the variables

-7m-(-8m+8)+13=0

We get rid of parentheses

-7m+8m-8+13=0

We add all the numbers together, and all the variables

m+5=0

We move all terms containing m to the left, all other terms to the right

m=-5

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