16-(9x-5)-33=4(1-2x)+10

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Solution for 16-(9x-5)-33=4(1-2x)+10 equation: 



16-(9x-5)-33=4(1-2x)+10

We move all terms to the left:

16-(9x-5)-33-(4(1-2x)+10)=0

We add all the numbers together, and all the variables

-(9x-5)-(4(-2x+1)+10)+16-33=0

We add all the numbers together, and all the variables

-(9x-5)-(4(-2x+1)+10)-17=0

We get rid of parentheses

-9x-(4(-2x+1)+10)+5-17=0



We calculate terms in parentheses: -(4(-2x+1)+10), so:

4(-2x+1)+10

We multiply parentheses

-8x+4+10

We add all the numbers together, and all the variables

-8x+14

Back to the equation:

-(-8x+14)



We add all the numbers together, and all the variables

-9x-(-8x+14)-12=0

We get rid of parentheses

-9x+8x-14-12=0

We add all the numbers together, and all the variables

-1x-26=0

We move all terms containing x to the left, all other terms to the right

-x=26

x=26/-1

x=-26

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