16-(m+1)=2(2m-1)

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Solution for 16-(m+1)=2(2m-1) equation: 



16-(m+1)=2(2m-1)

We move all terms to the left:

16-(m+1)-(2(2m-1))=0

We get rid of parentheses

-m-(2(2m-1))-1+16=0



We calculate terms in parentheses: -(2(2m-1)), so:

2(2m-1)

We multiply parentheses

4m-2

Back to the equation:

-(4m-2)



We add all the numbers together, and all the variables

-1m-(4m-2)+15=0

We get rid of parentheses

-1m-4m+2+15=0

We add all the numbers together, and all the variables

-5m+17=0

We move all terms containing m to the left, all other terms to the right

-5m=-17

m=-17/-5

m=3+2/5

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