16-(r+2)=10+3(r-7)

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Solution for 16-(r+2)=10+3(r-7) equation: 



16-(r+2)=10+3(r-7)

We move all terms to the left:

16-(r+2)-(10+3(r-7))=0

We get rid of parentheses

-r-(10+3(r-7))-2+16=0



We calculate terms in parentheses: -(10+3(r-7)), so:

10+3(r-7)

determiningTheFunctionDomain
3(r-7)+10

We multiply parentheses

3r-21+10

We add all the numbers together, and all the variables

3r-11

Back to the equation:

-(3r-11)



We add all the numbers together, and all the variables

-1r-(3r-11)+14=0

We get rid of parentheses

-1r-3r+11+14=0

We add all the numbers together, and all the variables

-4r+25=0

We move all terms containing r to the left, all other terms to the right

-4r=-25

r=-25/-4

r=6+1/4

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