16-2(3x+1)=(4x+1)

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Solution for 16-2(3x+1)=(4x+1) equation: 



16-2(3x+1)=(4x+1)

We move all terms to the left:

16-2(3x+1)-((4x+1))=0

We multiply parentheses

-6x-((4x+1))-2+16=0



We calculate terms in parentheses: -((4x+1)), so:

(4x+1)

We get rid of parentheses

4x+1

Back to the equation:

-(4x+1)



We add all the numbers together, and all the variables

-6x-(4x+1)+14=0

We get rid of parentheses

-6x-4x-1+14=0

We add all the numbers together, and all the variables

-10x+13=0

We move all terms containing x to the left, all other terms to the right

-10x=-13

x=-13/-10

x=1+3/10

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