16-2(3x+1)=4(x+11)

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Solution for 16-2(3x+1)=4(x+11) equation: 



16-2(3x+1)=4(x+11)

We move all terms to the left:

16-2(3x+1)-(4(x+11))=0

We multiply parentheses

-6x-(4(x+11))-2+16=0



We calculate terms in parentheses: -(4(x+11)), so:

4(x+11)

We multiply parentheses

4x+44

Back to the equation:

-(4x+44)



We add all the numbers together, and all the variables

-6x-(4x+44)+14=0

We get rid of parentheses

-6x-4x-44+14=0

We add all the numbers together, and all the variables

-10x-30=0

We move all terms containing x to the left, all other terms to the right

-10x=30

x=30/-10

x=-3

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