16-2(x+1)=4(1-x)

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Solution for 16-2(x+1)=4(1-x) equation: 



16-2(x+1)=4(1-x)

We move all terms to the left:

16-2(x+1)-(4(1-x))=0

We add all the numbers together, and all the variables

-2(x+1)-(4(-1x+1))+16=0

We multiply parentheses

-2x-(4(-1x+1))-2+16=0



We calculate terms in parentheses: -(4(-1x+1)), so:

4(-1x+1)

We multiply parentheses

-4x+4

Back to the equation:

-(-4x+4)



We add all the numbers together, and all the variables

-2x-(-4x+4)+14=0

We get rid of parentheses

-2x+4x-4+14=0

We add all the numbers together, and all the variables

2x+10=0

We move all terms containing x to the left, all other terms to the right

2x=-10

x=-10/2

x=-5

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