16-2(y+7)=4(y-7)-(y-1)

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Solution for 16-2(y+7)=4(y-7)-(y-1) equation: 



16-2(y+7)=4(y-7)-(y-1)

We move all terms to the left:

16-2(y+7)-(4(y-7)-(y-1))=0

We multiply parentheses

-2y-(4(y-7)-(y-1))-14+16=0



We calculate terms in parentheses: -(4(y-7)-(y-1)), so:

4(y-7)-(y-1)

We multiply parentheses

4y-(y-1)-28

We get rid of parentheses

4y-y+1-28

We add all the numbers together, and all the variables

3y-27

Back to the equation:

-(3y-27)



We add all the numbers together, and all the variables

-2y-(3y-27)+2=0

We get rid of parentheses

-2y-3y+27+2=0

We add all the numbers together, and all the variables

-5y+29=0

We move all terms containing y to the left, all other terms to the right

-5y=-29

y=-29/-5

y=5+4/5

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