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16-2t=t(3/2)+9
We move all terms to the left:
16-2t-(t(3/2)+9)=0
We add all the numbers together, and all the variables
-2t-(t(+3/2)+9)+16=0
We multiply all the terms by the denominator
-2t*2)+9)-(t(+3+16*2)+9)=0
We add all the numbers together, and all the variables
-2t*2)+9)-(t35+9)=0
Wy multiply elements
-4t^2=0
a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$t=\frac{-b}{2a}=\frac{0}{-8}=0$
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