16-3p=(2/3)p+5

Solution for 16-3p=(2/3)p+5 equation:

16-3p=(2/3)p+5

We move all terms to the left:

16-3p-((2/3)p+5)=0


Domain of the equation: 3)p+5)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

-3p-((+2/3)p+5)+16=0

We multiply all the terms by the denominator


-3p*3)p+5)-((+16*3)p+5)+2=0

We add all the numbers together, and all the variables

-3p*3)p+5)-(48p+5)+2=0

Wy multiply elements

-9p^2=0

a = -9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-9)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{-18}=0$