16-3p=(2/3)p+5

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Solution for 16-3p=(2/3)p+5 equation:



16-3p=(2/3)p+5
We move all terms to the left:
16-3p-((2/3)p+5)=0
Domain of the equation: 3)p+5)!=0
p!=0/1
p!=0
p∈R
We add all the numbers together, and all the variables
-3p-((+2/3)p+5)+16=0
We multiply all the terms by the denominator
-3p*3)p+5)-((+16*3)p+5)+2=0
We add all the numbers together, and all the variables
-3p*3)p+5)-(48p+5)+2=0
Wy multiply elements
-9p^2=0
a = -9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-9)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{-18}=0$

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