16-45=4(x-3)-5

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Solution for 16-45=4(x-3)-5 equation: 



16-45=4(x-3)-5

We move all terms to the left:

16-45-(4(x-3)-5)=0

We add all the numbers together, and all the variables

-(4(x-3)-5)-29=0



We calculate terms in parentheses: -(4(x-3)-5), so:

4(x-3)-5

We multiply parentheses

4x-12-5

We add all the numbers together, and all the variables

4x-17

Back to the equation:

-(4x-17)



We get rid of parentheses

-4x+17-29=0

We add all the numbers together, and all the variables

-4x-12=0

We move all terms containing x to the left, all other terms to the right

-4x=12

x=12/-4

x=-3

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