16-4y=2(y+2)

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Solution for 16-4y=2(y+2) equation: 



16-4y=2(y+2)

We move all terms to the left:

16-4y-(2(y+2))=0



We calculate terms in parentheses: -(2(y+2)), so:

2(y+2)

We multiply parentheses

2y+4

Back to the equation:

-(2y+4)



We get rid of parentheses

-4y-2y-4+16=0

We add all the numbers together, and all the variables

-6y+12=0

We move all terms containing y to the left, all other terms to the right

-6y=-12

y=-12/-6

y=+2

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