16-5(3d-4)=8(-2d+11)

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Solution for 16-5(3d-4)=8(-2d+11) equation:



16-5(3d-4)=8(-2d+11)
We move all terms to the left:
16-5(3d-4)-(8(-2d+11))=0
We multiply parentheses
-15d-(8(-2d+11))+20+16=0
We calculate terms in parentheses: -(8(-2d+11)), so:
8(-2d+11)
We multiply parentheses
-16d+88
Back to the equation:
-(-16d+88)
We add all the numbers together, and all the variables
-15d-(-16d+88)+36=0
We get rid of parentheses
-15d+16d-88+36=0
We add all the numbers together, and all the variables
d-52=0
We move all terms containing d to the left, all other terms to the right
d=52

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