16-5(3r-4)=8(-2r+11)

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Solution for 16-5(3r-4)=8(-2r+11) equation: 



16-5(3r-4)=8(-2r+11)

We move all terms to the left:

16-5(3r-4)-(8(-2r+11))=0

We multiply parentheses

-15r-(8(-2r+11))+20+16=0



We calculate terms in parentheses: -(8(-2r+11)), so:

8(-2r+11)

We multiply parentheses

-16r+88

Back to the equation:

-(-16r+88)



We add all the numbers together, and all the variables

-15r-(-16r+88)+36=0

We get rid of parentheses

-15r+16r-88+36=0

We add all the numbers together, and all the variables

r-52=0

We move all terms containing r to the left, all other terms to the right

r=52

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