16-5(3x+4)=8(-2x+11)

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Solution for 16-5(3x+4)=8(-2x+11) equation: 



16-5(3x+4)=8(-2x+11)

We move all terms to the left:

16-5(3x+4)-(8(-2x+11))=0

We multiply parentheses

-15x-(8(-2x+11))-20+16=0



We calculate terms in parentheses: -(8(-2x+11)), so:

8(-2x+11)

We multiply parentheses

-16x+88

Back to the equation:

-(-16x+88)



We add all the numbers together, and all the variables

-15x-(-16x+88)-4=0

We get rid of parentheses

-15x+16x-88-4=0

We add all the numbers together, and all the variables

x-92=0

We move all terms containing x to the left, all other terms to the right

x=92

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