16-5(7x-2)=13(x-2)+4(13-x)

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Solution for 16-5(7x-2)=13(x-2)+4(13-x) equation:



16-5(7x-2)=13(x-2)+4(13-x)
We move all terms to the left:
16-5(7x-2)-(13(x-2)+4(13-x))=0
We add all the numbers together, and all the variables
-5(7x-2)-(13(x-2)+4(-1x+13))+16=0
We multiply parentheses
-35x-(13(x-2)+4(-1x+13))+10+16=0
We calculate terms in parentheses: -(13(x-2)+4(-1x+13)), so:
13(x-2)+4(-1x+13)
We multiply parentheses
13x-4x-26+52
We add all the numbers together, and all the variables
9x+26
Back to the equation:
-(9x+26)
We add all the numbers together, and all the variables
-35x-(9x+26)+26=0
We get rid of parentheses
-35x-9x-26+26=0
We add all the numbers together, and all the variables
-44x=0
x=0/-44
x=0

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