16-8(x+3)=-10(x+2)+13

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Solution for 16-8(x+3)=-10(x+2)+13 equation: 



16-8(x+3)=-10(x+2)+13

We move all terms to the left:

16-8(x+3)-(-10(x+2)+13)=0

We multiply parentheses

-8x-(-10(x+2)+13)-24+16=0



We calculate terms in parentheses: -(-10(x+2)+13), so:

-10(x+2)+13

We multiply parentheses

-10x-20+13

We add all the numbers together, and all the variables

-10x-7

Back to the equation:

-(-10x-7)



We add all the numbers together, and all the variables

-8x-(-10x-7)-8=0

We get rid of parentheses

-8x+10x+7-8=0

We add all the numbers together, and all the variables

2x-1=0

We move all terms containing x to the left, all other terms to the right

2x=1

x=1/2

x=1/2

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