16-8x+4(x-6)=-(2x-3)-x+1+6

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Solution for 16-8x+4(x-6)=-(2x-3)-x+1+6 equation: 



16-8x+4(x-6)=-(2x-3)-x+1+6

We move all terms to the left:

16-8x+4(x-6)-(-(2x-3)-x+1+6)=0

We multiply parentheses

-8x+4x-(-(2x-3)-x+1+6)-24+16=0



We calculate terms in parentheses: -(-(2x-3)-x+1+6), so:

-(2x-3)-x+1+6

We add all the numbers together, and all the variables

-1x-(2x-3)+7

We get rid of parentheses

-1x-2x+3+7

We add all the numbers together, and all the variables

-3x+10

Back to the equation:

-(-3x+10)



We add all the numbers together, and all the variables

-4x-(-3x+10)-8=0

We get rid of parentheses

-4x+3x-10-8=0

We add all the numbers together, and all the variables

-1x-18=0

We move all terms containing x to the left, all other terms to the right

-x=18

x=18/-1

x=-18

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