16-m(m+-5)=-60

Solution for 16-m(m+-5)=-60 equation:

16-m(m+-5)=-60

We move all terms to the left:

16-m(m+-5)-(-60)=0

We add all the numbers together, and all the variables

-m(m-5)+16-(-60)=0

We add all the numbers together, and all the variables

-m(m-5)+76=0

We multiply parentheses

-m^2+5m+76=0

We add all the numbers together, and all the variables

-1m^2+5m+76=0

a = -1; b = 5; c = +76;
Δ = b2-4ac
Δ = 52-4·(-1)·76
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{329}}{2*-1}=\frac{-5-\sqrt{329}}{-2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{329}}{2*-1}=\frac{-5+\sqrt{329}}{-2}
$