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16/(3x-4)=5/x
We move all terms to the left:
16/(3x-4)-(5/x)=0
Domain of the equation: (3x-4)!=0
We move all terms containing x to the left, all other terms to the right
3x!=4
x!=4/3
x!=1+1/3
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
16/(3x-4)-(+5/x)=0
We get rid of parentheses
16/(3x-4)-5/x=0
We calculate fractions
16x/(3x^2-4x)+(-15x+20)/(3x^2-4x)=0
We multiply all the terms by the denominator
16x+(-15x+20)=0
We get rid of parentheses
16x-15x+20=0
We add all the numbers together, and all the variables
x+20=0
We move all terms containing x to the left, all other terms to the right
x=-20
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