16/120=j15

Simple and best practice solution for 16/120=j15 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 16/120=j15 equation: 


j in (-oo:+oo)

16/120 = j^15 // - j^15

16/120-j^15 = 0

-1*j^15 = -2/15 // : -1

j^15 = 2/15

j^15 = 2/15 // ^ 1/15

j = (2/15)^(1/15)

j = (2/15)^(1/15)

See similar equations:

| .10x+.25x(24-x)=4.50 | | n+-18= | | X+21+3x=-14-3x-21 | | 45/792=70/w | | 20-16p=4(5-4s) | | 12(m-2)=6 | | -1.2+x=-12 | | 5x+8y=201 | | 0=x^2+8x+16factoring | | ((5c^3v^3)/(2ab^2))-3x^3/8b^3c^2 | | 12x-(5+3x)= | | 18X-2X^2=0 | | -21(z+177)=210 | | 14-3r/2=22 | | (x^2-2y^2)dx+(xy)dy=0 | | 1.8e+4=x | | x(8/12)=7 | | 60x-3x2/3x | | (x^2-2y^2)dc+(xy)dy=0 | | 6x+3+7x+12=180 | | .000044145x=.000361x^2 | | 4u/5=24 | | 4/(2x)=0 | | 6+3x=-10+2x | | (40x)+(5*1.5x)=600 | | 2(log[2](4x)-3)-log[3](2x+3)=2 | | 13x-(5+9x)= | | (40x)+(10*1.5x)=600 | | 8y=16/9 | | 4+(x-9)=2*(x+3) | | .8=16c | | 1/2(2x-6)=22 |

Equations solver categories