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16/25x+18=x
We move all terms to the left:
16/25x+18-(x)=0
Domain of the equation: 25x!=0We add all the numbers together, and all the variables
x!=0/25
x!=0
x∈R
-1x+16/25x+18=0
We multiply all the terms by the denominator
-1x*25x+18*25x+16=0
Wy multiply elements
-25x^2+450x+16=0
a = -25; b = 450; c = +16;
Δ = b2-4ac
Δ = 4502-4·(-25)·16
Δ = 204100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{204100}=\sqrt{100*2041}=\sqrt{100}*\sqrt{2041}=10\sqrt{2041}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(450)-10\sqrt{2041}}{2*-25}=\frac{-450-10\sqrt{2041}}{-50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(450)+10\sqrt{2041}}{2*-25}=\frac{-450+10\sqrt{2041}}{-50} $
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