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16/3x=x-15
We move all terms to the left:
16/3x-(x-15)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
16/3x-x+15=0
We multiply all the terms by the denominator
-x*3x+15*3x+16=0
Wy multiply elements
-3x^2+45x+16=0
a = -3; b = 45; c = +16;
Δ = b2-4ac
Δ = 452-4·(-3)·16
Δ = 2217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2217}}{2*-3}=\frac{-45-\sqrt{2217}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2217}}{2*-3}=\frac{-45+\sqrt{2217}}{-6} $
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