16/3z+(-2)=-9

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Solution for 16/3z+(-2)=-9 equation: 



16/3z+(-2)=-9

We move all terms to the left:

16/3z+(-2)-(-9)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R



We add all the numbers together, and all the variables

16/3z+7=0

We multiply all the terms by the denominator


7*3z+16=0

Wy multiply elements

21z+16=0

We move all terms containing z to the left, all other terms to the right

21z=-16

z=-16/21

z=-16/21

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