16/x-6-192/x2-36=1

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Solution for 16/x-6-192/x2-36=1 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

16/x-(192/(x^2))-36-6 = 1 // - 1

16/x-(192/(x^2))-36-6-1 = 0

16/x-192*x^-2-36-6-1 = 0

16*x^-1-192*x^-2-43 = 0

t_1 = x^-1

16*t_1^1-192*t_1^2-43 = 0

16*t_1-192*t_1^2-43 = 0

DELTA = 16^2-(-192*(-43)*4)

DELTA = -32768

DELTA < 0

x belongs to the empty set

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