160-10x=40-2x

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Solution for 160-10x=40-2x equation: 



160-10x=40-2x

We move all terms to the left:

160-10x-(40-2x)=0

We add all the numbers together, and all the variables

-10x-(-2x+40)+160=0

We get rid of parentheses

-10x+2x-40+160=0

We add all the numbers together, and all the variables

-8x+120=0

We move all terms containing x to the left, all other terms to the right

-8x=-120

x=-120/-8

x=+15

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