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160-x=1/4x
We move all terms to the left:
160-x-(1/4x)=0
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-x-(+1/4x)+160=0
We add all the numbers together, and all the variables
-1x-(+1/4x)+160=0
We get rid of parentheses
-1x-1/4x+160=0
We multiply all the terms by the denominator
-1x*4x+160*4x-1=0
Wy multiply elements
-4x^2+640x-1=0
a = -4; b = 640; c = -1;
Δ = b2-4ac
Δ = 6402-4·(-4)·(-1)
Δ = 409584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{409584}=\sqrt{16*25599}=\sqrt{16}*\sqrt{25599}=4\sqrt{25599}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(640)-4\sqrt{25599}}{2*-4}=\frac{-640-4\sqrt{25599}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(640)+4\sqrt{25599}}{2*-4}=\frac{-640+4\sqrt{25599}}{-8} $
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