If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1600=4x^2
We move all terms to the left:
1600-(4x^2)=0
a = -4; b = 0; c = +1600;
Δ = b2-4ac
Δ = 02-4·(-4)·1600
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25600}=160$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*-4}=\frac{-160}{-8} =+20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*-4}=\frac{160}{-8} =-20 $
| x/8+11=13 | | 583x−=−8 | | t-145=-139 | | 90=4x+8+5x+1 | | 6x-98=x-63 | | 17+4a=-11 | | 2(6x-98)=x-63 | | 40+2z=60 | | 7x^2+4=3x | | n/2+5.4=9.8 | | 180=4k+50+8k+178 | | 6w-5/2=-5/2w-1/5 | | x+5^2=7 | | 2000x=(3840)0.8 | | 2(2z+5)=2(2z+5)= 50 | | 5/9+3j=-2/3 | | y+9=12* | | -12(4−4x)=4x+12 | | 13+7x=23 | | x-9^2=1 | | 2d=5=19 | | 87=5j+17 | | -10=6(x-10) | | 6×-5y=0 | | 12=x/5-10 | | 1800*2=x*4 | | 0=X^4+5x^2-6 | | 8=25x+7, | | (D5–5D4+7D3+D2–8D+4)y=0 | | 5.5g+6=2.5g+15 | | 378-y=142 | | –5c+–4c+3c−-9c=12 |