160=(x)(x+6)

Solution for 160=(x)(x+6) equation:

160=(x)(x+6)

We move all terms to the left:

160-((x)(x+6))=0


We calculate terms in parentheses: -(x(x+6)), so:

x(x+6)

We multiply parentheses

x^2+6x

Back to the equation:

-(x^2+6x)


We get rid of parentheses

-x^2-6x+160=0

We add all the numbers together, and all the variables

-1x^2-6x+160=0

a = -1; b = -6; c = +160;
Δ = b2-4ac
Δ = -62-4·(-1)·160
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-26}{2*-1}=\frac{-20}{-2}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+26}{2*-1}=\frac{32}{-2}
=-16
$