160=(x+8)(x+6)

Solution for 160=(x+8)(x+6) equation:

160=(x+8)(x+6)

We move all terms to the left:

160-((x+8)(x+6))=0

We multiply parentheses ..

-((+x^2+6x+8x+48))+160=0


We calculate terms in parentheses: -((+x^2+6x+8x+48)), so:

(+x^2+6x+8x+48)

We get rid of parentheses

x^2+6x+8x+48

We add all the numbers together, and all the variables

x^2+14x+48

Back to the equation:

-(x^2+14x+48)


We get rid of parentheses

-x^2-14x-48+160=0

We add all the numbers together, and all the variables

-1x^2-14x+112=0

a = -1; b = -14; c = +112;
Δ = b2-4ac
Δ = -142-4·(-1)·112
Δ = 644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{644}=\sqrt{4*161}=\sqrt{4}*\sqrt{161}=2\sqrt{161}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{161}}{2*-1}=\frac{14-2\sqrt{161}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{161}}{2*-1}=\frac{14+2\sqrt{161}}{-2}
$