If it's not what You are looking for type in the equation solver your own equation and let us solve it.
160=-2x-3(4x-2)
We move all terms to the left:
160-(-2x-3(4x-2))=0
We calculate terms in parentheses: -(-2x-3(4x-2)), so:We get rid of parentheses
-2x-3(4x-2)
We multiply parentheses
-2x-12x+6
We add all the numbers together, and all the variables
-14x+6
Back to the equation:
-(-14x+6)
14x-6+160=0
We add all the numbers together, and all the variables
14x+154=0
We move all terms containing x to the left, all other terms to the right
14x=-154
x=-154/14
x=-11
| 4(-10+5x)=-135 | | 5h−-22=67 | | 2y-19=1 | | -4=4-2n | | -218=-4x-7(-x+26) | | h=3−2h | | 6(7-4x)=162 | | v/2+1=4 | | 8(-14x-23)=1384 | | -10(15x+17)=1030 | | 6x2−17x+15=3x2 | | 2m−-1=7 | | .d/75=25 | | -102+14x=-438 | | 5u=5+6u | | (11+07+12+x)/4=12 | | 165-26x=-21x-70 | | 6p+14=26 | | 4q=7+5q | | -13=2z+-7 | | -72-8x=45-5x | | (11+07+12+x)=12 | | 9x+6=3(2x+5) | | 5x-3=9x-1 | | 3x−1/12=3/14 | | -3(10+5x)=-135 | | 27=4x+7+-10 | | 3x−112=314 | | 5−-u=1 | | b/3+11=15 | | 2q^2–3q–14=0 | | 7=13-2y |