160=16x(7-x)

Solution for 160=16x(7-x) equation:

160=16x(7-x)

We move all terms to the left:

160-(16x(7-x))=0

We add all the numbers together, and all the variables

-(16x(-1x+7))+160=0


We calculate terms in parentheses: -(16x(-1x+7)), so:

16x(-1x+7)

We multiply parentheses

-16x^2+112x

Back to the equation:

-(-16x^2+112x)


We get rid of parentheses

16x^2-112x+160=0

a = 16; b = -112; c = +160;
Δ = b2-4ac
Δ = -1122-4·16·160
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-48}{2*16}=\frac{64}{32}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+48}{2*16}=\frac{160}{32}
=5
$