160=4(10+3k)

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Solution for 160=4(10+3k) equation: 



160=4(10+3k)

We move all terms to the left:

160-(4(10+3k))=0

We add all the numbers together, and all the variables

-(4(3k+10))+160=0



We calculate terms in parentheses: -(4(3k+10)), so:

4(3k+10)

We multiply parentheses

12k+40

Back to the equation:

-(12k+40)



We get rid of parentheses

-12k-40+160=0

We add all the numbers together, and all the variables

-12k+120=0

We move all terms containing k to the left, all other terms to the right

-12k=-120

k=-120/-12

k=+10

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