162-50x2=0

Solution for 162-50x2=0 equation:

162-50x^2=0

a = -50; b = 0; c = +162;
Δ = b2-4ac
Δ = 02-4·(-50)·162
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*-50}=\frac{-180}{-100}
=1+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*-50}=\frac{180}{-100}
=-1+4/5
$