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162=(2a)2
We move all terms to the left:
162-((2a)2)=0
determiningTheFunctionDomain -2a2+162=0
We add all the numbers together, and all the variables
-2a^2+162=0
a = -2; b = 0; c = +162;
Δ = b2-4ac
Δ = 02-4·(-2)·162
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*-2}=\frac{-36}{-4} =+9 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*-2}=\frac{36}{-4} =-9 $
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