162=(n-2)*180/n

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Solution for 162=(n-2)*180/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

162 = (180*(n-2))/n // - (180*(n-2))/n

162-((180*(n-2))/n) = 0

162-180*n^-1*(n-2) = 0

162-180*n^-1*(n-2) = 0

360*n^-1-18 = 0

360*n^-1-18 = 0

360*n^-1 = 18 // : 360

n^-1 = 1/20

-1 < 0

1/(n^1) = 1/20 // * n^1

1 = 1/20*n^1 // : 1/20

20 = n^1

n = 20

n = 20

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