162=3(4+8r)+6

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Solution for 162=3(4+8r)+6 equation: 



162=3(4+8r)+6

We move all terms to the left:

162-(3(4+8r)+6)=0

We add all the numbers together, and all the variables

-(3(8r+4)+6)+162=0



We calculate terms in parentheses: -(3(8r+4)+6), so:

3(8r+4)+6

We multiply parentheses

24r+12+6

We add all the numbers together, and all the variables

24r+18

Back to the equation:

-(24r+18)



We get rid of parentheses

-24r-18+162=0

We add all the numbers together, and all the variables

-24r+144=0

We move all terms containing r to the left, all other terms to the right

-24r=-144

r=-144/-24

r=+6

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