162=3(4+8r)+6

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Solution for 162=3(4+8r)+6 equation:



162=3(4+8r)+6
We move all terms to the left:
162-(3(4+8r)+6)=0
We add all the numbers together, and all the variables
-(3(8r+4)+6)+162=0
We calculate terms in parentheses: -(3(8r+4)+6), so:
3(8r+4)+6
We multiply parentheses
24r+12+6
We add all the numbers together, and all the variables
24r+18
Back to the equation:
-(24r+18)
We get rid of parentheses
-24r-18+162=0
We add all the numbers together, and all the variables
-24r+144=0
We move all terms containing r to the left, all other terms to the right
-24r=-144
r=-144/-24
r=+6

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